Question

meena wants to make a cloth mask by joining two equal size triangular pieces of sides 5cm,8cm and 5cm . how much cloth has she required ​

Answer 1

Given :- meena wants to make a cloth mask by joining two equal size triangular pieces of sides 5cm, 8cm, and 5cm. How much cloth has she required ?

Solution :

we know that,

• when sides of A are given as a, b and c, than,
• semi perimeter (s)=(a + b + c)/2.
• Area of A = √[s * (s - a) * (s -b) * (s -c)]

given that, sides of triangular pieces are 5cm, 8cm and 5cm.

So,

→ s=(5+8+5)/2 =18/2 = 9cm.

Than,

→ Area of one triangular piece = √[9 * (9 - 5) *(9 - 8)*(9- 5)) = √[9* 4 * 1* 4] = √(3²* 4²) = 3*4= 12 cm².

Therefore,

→ Total area of two triangular pieces = 12 * 2 = 24 cm². (Ans.)

Hence Meens reuired 24cm² cloth to make cloth mask.

Learn more :

ABCD is a rhombus with A = 60° , BC = (3x+5)cm , CD =(6x-10)cm and AC =(3y-1)cm. Find

x and y.

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3.

In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

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Answer 2

Answer:

24

Step-by-step explanation:

We are given the dimensions of triangle as 5,5, 8.

Now area of triangle is

Area = 1/2 × base × height

Now in this case we know the base which is 8.

In order to find the height, we will use the pythagoras theorem where

H = 5,

Base = 4

Perpendicular = ?

Now applying pythagoras theorem,

Perpendicular = 3

This is the height of given triangle.

Area of triangle = 1/2 × 8 × 3

Area of one triangle = 12

So area of both triangles = 12 + 12 = 24