Question

Meena went to a bank to withdraw Rs.2000. She asked the cashier to give Rs. 50 and Rs. 100 notes only . Meena got 25 notes in all . Find how many notes of Rs.50 and Rs.100 she received by elimination method​

Answer 1

Answer:

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Step-by-step explanation:

1. Let the number of Rs 50 notes and Rs 100 notes be x and y. Hence, Meena has 10 notes of Rs 50 and 15 notes of Rs 100.

Answer 2

Question :

Meena went to a bank to withdraw Rs.2000. She asked the cashier to give Rs. 50 and Rs. 100 notes only . Meena got 25 notes in all . Find how many notes of Rs.50 and Rs.100 she received by elimination method​

Given :

• There are 25 notes  

• Let the number of ₹50 notes be x

• Let the number of ₹100 notes be y

• Total amount withdrawn = 2000

Solution :

(Number of ₹50 notes + Number of ₹100 notes)

$x + y = 25 \to 1$

$\begin{array}{|c|c|c|}\cline{1-3}\bf Ruppes \ 50 \ Notes &\bf Ruppes \ 100 \ Notes &\bf Total \ Amount \\\cline{1-3}\sf 1&\tt 2 &\tt 50\times 1+100\times 2=50+200=250 \\\cline{1-3}\sf 2&\tt 3 &\tt 50\times 2 +100\times 3=100+300=400\\\cline{1-3}\sf x&\tt y &\tt 50\times x+100\times y=50x+100y\\\cline{1-3}\end{array}$

Therefore,

$50x + 100y = 2000\\\\\\50 (x +2y) = 2000\\\\\\x+2y=\frac{2000}{50}\\\\\\x+2y=40\to2$

Hence, the equations are :

$x + y = 25 \to 1$

$x+2y=40\to2$

$\textsf{Using elimination method }\\\\+x+y=25\\-x-2y=40\\-y=-15\\\\y=15$

Putting the value of y in 1

$x+y=25\\\\\\x+15=25\\\\\\x=25-15\\\\\\x=10$

Therefore, x = 10 and y = 15 are solutions for the equation

Answer :

Therefore,

• The number of ₹ 50 notes are 10

• The number of ₹ 100 notes are 15

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