Question

Meena went to bank to withdraw 2000 . She asked the cashier to give her 50 and 100 notes only. Meena got 25 notes in all . Find how many notes of 50 and 100 she received

Answer 1

Answer:

Let the Rs.50 notes by x and Rs.100 notes be y.

∴ Total notes =(x+y) notes

Total notes (given) =25 notes

∴(x+y)=25⟶(i)

Total money Meena has=50x+100y

Total money (given) =Rs.2000

On simplification,

x+2y=40⟶(ii)

On substraction (i) and (ii),

−y=−15

y=15 notes

putting y in (i)

x+y=25

x=10 notes

∴ Rs.50 notes=10 notes.

Rs.100 notes=15 notes

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Answer 2

$\huge \sf Answer :$

Rs 50 notes = 10 and Rs 100 notes = 15

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$\huge \sf Solution :$

Let total Rs 50 notes = x

and total Rs 100 notes = y

∴ Total notes = x + y

But we are given total notes = 25

$\sf \implies x+y = 25 \: \: - ①$

Now, Meena has total money =50x + 100y

But we are given total money =Rs 2000

$\sf \implies 50x+100y=2000$

$\sf \implies 50(x+2y)=2000$

$\sf \implies x+2y = \dfrac{2000}{50}$

$\sf \implies x+2y = \dfrac{\cancel{2000}^{40}}{\cancel{50}}$

$\sf \implies x+2y = 40 \: \: - ②$

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On substraction of ① and ②,

(x+y) - (x+2y) = 25 - 40

x + y - x - 2y = - 15

- y = - 15

$\boxed{\sf y = 15}$ ⠀

Now, by putting y in ①,

x+y=25

x + 15 = 25

x = 25 - 15

$\boxed{\sf x=10}$

∴ Rs 50 notes, x = 10

and Rs 100 notes, y = 15