Question

Meenakshi wants to make a bird bath in cylindrical shape for his garden. She decided make a cylinder of 1.5 m and radius 0.5 m with a hemispherical depression at one end. This cylinder stands on three cylindrical pillars of radius 7 cm and height 2 m using POP as shown in following figure. Q. 13. The curved surface area of the cylindrical part is : (A) 4 m2 (B) 4.71 m2 (C) 5.3 m2 (D) 6.9 m2 Q. 14. The curved surface area of hemispherical depression is: (A) 1 m2 (B) 1.57 m2 (C) 2.5 m2 (D) 2.57 m2 Q. 15. The volume of the three pillars is: (A) 0.0924 m3 (B) 0.94 m3 (C) 9 m3 (D) 9.43 m3 Q. 16. Curved surface area of 3 pillars is: (A) 1.63 m2 (B) 2 m2 (C) 2.64 m2 (D) 37.71 m2 Q. 17. The volume of the hemispherical depression is: (A) 0.26 m3 (B) 0.72 m3 (C) 0.82 m3 (D) None of thes​

Answer 1

Step-by-step explanation:

Let r be the common radius of the cylinder and hemisphere and h be the height of the hollow cylinder.

Then r=30cm;h=1.45m=145cm

Total surface are of the bird-bath = curved surface area of the cylinder + curved surface area of the hemisphere

=2πrh+2πr

2

=2π(h+r)

=2×

7

22

×30(145+30)cm

2

=3.3m 2

Answer 2

Answer:

take this

Step-by-step explanation:

1. 4.71 m square

2. 1.57 m square

3. 0.0924 m cube

4. I don't know