Math, asked by Anonymous, 2 months ago


Meenu bought two fans for 1200 each. She sold one at
a loss of 5% and the other at a profit of 10%. Find the selling price of each. Also find out the total profit or loss.​​

Answers

Answered by kmeenamodel
5

Answer:

Answer

Given C.P of first fan = Rs 1200

He sold the fan at a loss of 5%

⇒ Loss on first fan= 5% of 1200

= 5/100*1200

= Rs 60

S.P of fan = C.P - loss

= 1200 -60

= Rs 1140

C.P of 2nd fan = Rs 1200

He sold at a profit of 10%

profit of second fan= 10% of 1200

= 10/100*1200

= Rs 120

S.P of 2nd fan = profit + C.P

= 1200+120

= Rs 1320

Total cost price of two fans = 1200 + 1200 = Rs 2400

Total S.P of 2 fans = 1320+1140 = Rs 2460

Since S.P > C.P

He got profit on whole

profit = S.P - C.P

= 2460 - 2400

= Rs 60

Profit% = profit/C.P * 100

= 60/2400 * 100

= 2.5% profit on whole

Answered by mansioberoi10
2

Given C.P of first fan = Rs 1200

He sold the fan at a loss of 5%

⇒ Loss on first fan= 5% of 1200

= 5/100*1200

= Rs 60

S.P of fan = C.P - loss

= 1200 -60

= Rs 1140

C.P of 2nd fan = Rs 1200

He sold at a profit of 10%

profit of second fan= 10% of 1200

= 10/100*1200

= Rs 120

S.P of 2nd fan = profit + C.P

= 1200+120

= Rs 1320

Total cost price of two fans = 1200 + 1200 = Rs 2400

Total S.P of 2 fans = 1320+1140 = Rs 2460

Since S.P > C.P

He got profit on whole

profit = S.P - C.P

= 2460 - 2400

= Rs 60

Profit% = profit/C.P * 100

= 60/2400 * 100

= 2.5% profit on whole

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