Math, asked by biswashkhanal10, 6 months ago

Meera bought two cows for Rs 10000. If she sold one at a loss of 30% and other at a profit of 30%
and then she found that each cow was sold for the same price, find the percentage of profit or loss in whole transaction.​

Answers

Answered by Anonymous
12

Answer:

Step-by-step explanation:

Given,

CP of both the cows together = 10,000

Let the CP of one cow be x which was sold at  a loss of 30 %

Therefore,

The CP of another cow will be 10,000 - x which was sold at a profit of 30 %

One cow is sold at a loss of 30%

We know that Loss% = Loss/CP x 100

Therefore,

30 = 100Loss/x

Loss = 30x/100 = 3x/10

We know that,

Loss = CP - SP

3x/10 = x - SP

SP = x - 3x/10 = 7x/10

Another cow is sold at 30% profit

We know that Profit% = Profit/CP x 100

Therefore,

30 = 100Profit/(10,000 - x)

30(10000 - x) = 100Profit

(300000  - 30x)/100 = Profit

Profit = 3000 - 3x/10

We know that,

Profit = SP - CP

3000 - 3x/10 = SP - (10000 - x)

3000 - 3x/10 = SP - 10000 + x

SP = 13000 - 13x/10

According to the question,

Both cow's SP is the same

Therefore,

7x/10 = 13000 - 13x/10

20x/10 = 13000

2x = 13000

x = 6500

Therefore,

SP of the cow which was sold at a loss of 30% = (7 x 6500)/10 = 4,550

SP of the cow which was sold at a profit of 30% = 13000 - (13 x 6500)/10 = 4,550

Total SP = 9100

Total CP = 10000

As CP > SP,

Therefore,

There is a loss

Loss = CP - SP = 10000 - 9100 = 900

Loss% = Loss/CP x 100 = 900/10000 x 100 = 9 %

Therefore,

There is a  loss of 9% on the whole transaction

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