Question

meera is now 10 years older than her twin brothers . after 3 years from now, thrice her age will be four times the sum of her brother's age ago, find meeras present age?

Answer 1

Let the age of Meera be x.

Let the age of her twin brothers be y.

Given that Meera is now 10 years older than her twin brothers.

x = y + 10 ----- (1)


3 years hence:

The age of Meera = x + 3.

The age of her twin brother = y + 3.

Given that 3 years from now, thrice her age will be 4 times the sum of her brother's age ago.

3(x + 3) = 4(2(y + 3)

3x + 9 = 4(2y + 6)

3x + 9 = 8y + 24

3(y + 10) + 9 = 8y + 24

3y + 30 + 9 = 8y + 24

3y + 39 = 8y + 24

3y = 8y + 24 - 39

3y = 8y - 15

3y - 8y = -15

-5y = -15

y = 3

Substitute y = 3 in (1), we get

x = y + 10

x = 3 + 10

x = 13.

Therefore the present age of Meera = 13 years.


Hope this helps!...

Answer 2

Let Meera's Age be -
$x$

Let the age her twin brother's be -
$y$

Given that Meera is now 10 years older than her twin Brother's -
$x = y + 10$

3 years hence,
AGE OF MEERA =
$x + 3$

AGE OF HER TWIN BROTHER'S =
$y + 3$

Given that 3 years from now 3 times her age will be 4 times the sum of her Brother's age . . .

$3(x + 3) = 4(2(y + 3))$
$3x + 9 = 4(2y + 6)$
$3x + 9 = 8y + 24$
$x = y + 10$
$3(y + 10) + 9 = 8y + 24$
$3y + 30 + 9 = 8y + 24$
$3y + 39 = 8y + 24$
$39 - 24 = 8y - 3y$
$15 = 5y$
$y = 3$

Therefore, her Twin Brother's are 3 years old ; while Meera is 3 + 10 = 13 years old . . .
Hope this helps!