Math, asked by savita1021987, 1 month ago

Meesha's age is 8 years More than twice her daughter's age. four years ago, meesha's age was 7/2 times her daughter's age. what is her daughter's present age?

Answers

Answered by devitara287
0

Answer:

Mother is 5x years old.

In 27 years the daughter is x+27

The mother is 5x+27

5x+27=2(x+27)

5x+27=2x+54

3x=27

x=9, daughter’s age.

45 is mum’s age.

Step-by-step explanation:

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Answered by rk156747
0

Answer:

12years

Step-by-step explanation:

2d+8=m

4year earlier

7/2(d-4)=m-4

7d-28=2m-8

2m=7d-20

so

4d+16=7d-20

3d=36

d=12

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