Question

Meeta and Ria together ate ⅚ of a pizza.

If Meeta ate 3/12 of a pizza, how much pizza did Ria eat?

Answer 1

Given: Total pizza eaten by Meeta and Ria = 5 / 6

           Meeta ate 3 / 12 of the pizza, we have to find the part eaten by Ria

Let us assume that Ria ate x part of the pizza

Then, the given condition can be mathematically represented as

         $\frac{3}{12} + x =\frac{5}{6}$

                 $x=\frac{5}{6} -\frac{3}{12}$

                 $x=\frac{10}{12} -\frac{3}{12}$

                $x=\frac{7}{12}$

Hence, Ria ate 7/12th part of the pizza .

Answer 2

Question:-

Meeta and Ria together ate ⅚ of a pizza.  If Meeta ate 3/12 of a pizza, how much pizza did Ria eat?

Answer:-

Given:-

The portion of pizza which Meeta and Ria ate together = $\frac{5}{6}$

The portion of pizza which Meeta ate = $\frac{3}{12}$

To find:-

The portion of pizza which Ria ate.

Solution:-

The portion of pizza which Ria ate

= The portion of pizza which Meeta and Ria ate together - The portion of pizza which Meeta ate.

= $\frac{5}{6}-\frac{3}{12}$

= $\frac{10}{12} -\frac{3}{12}$ (LCM of 6 and 12 is 12)

= $\frac{10-3}{12}$

= $\frac{7}{12}$

∴ The portion of pizza which Ria ate = $\frac{7}{12}$

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