meeta is twice as old as Aarushi 5 years old her age was three times aarushi's age find the present age
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let the aarushi's present age=x yrs
meeta's Present age=2x yrs
before 5 yrs,
aarushi's age=x-5yrs
meeta's age =2x-5 yrs
ATQ
3(x-5)=2x-5
3x-15=2x-5
3x-2x=-5+15
1x=10
arushi's present age=x=10 yrs
meeta's age= 2x=2×10=20yrs
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