Question

meeting
© ABC is a triangle and
PQ is a straight line
AB in P & Acin Do If Ap=10m & Bp=360
AQ=105cm, CQ = 405cm.
Prove that
Car of AAPQ) tolar of ABC)​

Answer 1

Answer:

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Answer 2

Answer:

Given : In ΔABC, PQ is a line segment intersecting AB at P and AC at Q. AP = 1 cm , PB = 3cm, AQ= 1.5 cm and QC= 4.5cm.

In ∆APQ and ∆ABC,

∠A = ∠A               [Common]

AP/AB = AQ/AC        [Each equal to 1/4]

∆APQ ~ ∆ABC      [By SAS similarity]

We know that the ratio of the two similar triangles is equal to the ratio of the squares of their corresponding sides

ar∆APQ /ar∆ABC = (AP/AB)²

ar∆APQ /ar∆ABC = ( ¼)²

ar∆APQ /ar∆ABC = 1/16

ar∆APQ =  1/16 × ar∆ABC  

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