Math, asked by Rajan1374, 11 months ago

Meeting is to be addressed by 5 speakers a, b, c, d,



e. In how many ways can the speakers be ordered if b must not precede a (immediately or otherwise) :

Answers

Answered by amitnrw
5

Answer:

60 Ways

Step-by-step explanation:

Meeting is to be addressed by 5 speakers a, b, c, d, e. In how many ways can the speakers be ordered if b must not precede a (immediately or otherwise) :

5 Speaker can address in 5! ways = 120

Either b can speak before a  Or after a

ways  the speakers be ordered if b must not precede a  = 120/2 = 60 Ways

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