Question

Megan is twice as old as Anne. Six years ago, Megan was 4 times as old as Anne. How old are they now?

Answer 1

The age of "Anne is 9 years" and the age of "Megan is 18 years".

Step-by-step explanation:

Let the age of Anne be x years.

∴ The age of Megan =2x years

Six years ago,

The age of Anne = (x - 6) years

The age of Megan = (2x - 6) years

According to question,

2x - 6 = (x - 6) × 4

⇒ 2x - 6 = 4x - 24

⇒ 2x = 18

⇒ x = 9

∴ 2x = 2 × 9 = 18

Hence, the age of Anne is 9 years and the age of Megan is 18 years.