Question

megha placed an object 18cm in front of concave mirror she observes 4cm image at a distance of 14.4cm in front of mirror find height of the object?​

Answer 1

Explanation:

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u = distance of object = -18cm

(remember u is always negative)

h2 = height of image = 4

v = image distance = 14.4

We know one formula..

$magnification = \frac{ - v}{u} \\ m = \frac{ - 14.4}{ - 18} \\ m = 0.8$

$m = \frac{h1}{h2}$

$0.8 = \frac{h1}{4} \\ h1 = 3.2$

Where h1 = height of object.....

Answer 2

Answer:

+5cm

Explanation:

We know that

hi/ho = -v/u

So,

ho= (hi x u)/ho

ho= (-4 x -18)/14.4

ho= 5