Question

Mehak accelerate his scooty uniformly from 80km/hr to 40km/hr into 5 seconds calulate accerlation and distance

Answer 1

Given,

u= 22.2m/s

v= 11.1m/s

t= 5 sec

Now,

v= u-at

11.1= 22.2-5a

5a= 11.1

a = 2.22m/s^2.

Now,

s= ut - 1/2at^2

S = 22.2*5 - 1/2* 2.22*25

s = 83.25 m

so, the acceleration is 2.22m/s^2 and the distance covered is 83.25 m.