Question

Mehtab tells his daughter, “Five years ago, I was seven times as old as you were then. Also five years from now I shall be three times as old as you will be.” (Isn’t this interesting ?) Represent this situation algebraically and graphically. Algebraically, it is written as follow : If x and y are age of Mehtab and his daughter in years then x – 7y + 30 = 0 ....(i) x – 3y – 10 = 0 ....(ii)​

Answer 1

Let the fathers age be x years and his son be y years.

Therefore, seven years ago, age of father =  (x-7) 

and age of son = (y - 7)

According to the given condition,

x-7 =7(y-7) 

or x-7y = -42 ...(1)

After 3 years, fathers age = x+3  and

 son's age = (y+3)

As per given condition,

 x+3 = 3(y+3) 

 x-3y = 6 ...(2)

ON subtracting (2) from (1), we get

x - 7y - (x -3y) = -42 - 6

⇒ -4y = -48

⇒ y = 12

On putting value of y in (2), we get

x - 3(12) = 6

⇒ x = 6 + 36 = 42

Hence, present father's age = 42 years

and present son's age = 12 years.

here MATE HOPE its HELPFUL

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good NIGHT

Answer 2

Let the fathers age be x years and his son be y years.

Therefore, seven years ago, age of father = (x-7)

and age of son = (y - 7)

According to the given condition,

x-7 =7(y-7)

or x-7y = -42 ...(1)

After 3 years, fathers age = x+3 and

son's age = (y+3)

As per given condition,

x+3 = 3(y+3)

x-3y = 6 ...(2)

ON subtracting (2) from (1), we get

x - 7y - (x -3y) = -42 - 6

⇒ -4y = -48

⇒ y = 12

On putting value of y in (2), we get

x - 3(12) = 6

⇒ x = 6 + 36 = 42

Hence, present father's age = 42 years

and present son's age = 12 years.