Question

Meiling is thibking of three numbers. the sum of first two number is 738. the second number is 42 more than the third number. The third number is twice the first number .Find the difference between the first number and the second number​

Answer 1

Answer:

Let three numbers are x, y, z

So from problem given we can get equations as

x + y+z= 66

x=2y

z=1x/3

now we will make equation 1 with only one variable using equation 2 and 3.

y=1x/2 since x=2y

Now using equations 1, 3 and 5 we will get

x+1x/2+1x/3=66

11x/6=66

x= 66*6/11

x= 36

y=x/2=36/2=18

z=x/3=36/3=12

Hence the numbers are 36, 18 and 12

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Answer 2

Answer:

42÷738 = 7⁄123 is the answer