melal 7x104
The threshold frequency (vo) of a
of the photoelecion emitted when a
radration of frequency
frequency 1x 105 st
falls on the metal
Answers
Answered by
1
Explanation:
ANSWER
Given that,
v
o
=7.0×10
14
s
−1
v=1.0×10
15
s
−1
As we know, hv=hv
0
+
2
1
mv
2
i.e. h(v−v
0
)=K.E.
∴K.E.=(6.626×10
−34
)×(1.0×10
15
−7.0×10
14
)=6.626×10
−34
×10
14
(10−7)
∴K.E=19.878×10
−20
J
Similar questions