melting point of 3 substances a, b, c are 52 ° c, 175 ° c and 80 ° c. Arrange them in the decreasing order of the interparticle force of attraction in each of them. Give reason for your answer
Answers
Answered by
3
(175,80,52)°C
The reasons are as follows:
175°C=Has a large cohesive force(interparticle force) that is why a lot of heat is required to break the force of attraction and increase the kinetic enérgy!
75°C=Less cohesive force less heat required.
52°C=least cohesive force least heat required.
Hope you got your answer!
The reasons are as follows:
175°C=Has a large cohesive force(interparticle force) that is why a lot of heat is required to break the force of attraction and increase the kinetic enérgy!
75°C=Less cohesive force less heat required.
52°C=least cohesive force least heat required.
Hope you got your answer!
Answered by
0
Answer:
(175,80,52)°C
Explanation:
The reasons are as follows:
175°C=Has a large cohesive force(interparticle force) that is why a lot of heat is required to break the force of attraction and increase the kinetic enérgy!
80°C=Less cohesive force less heat required.
52°C=least cohesive force least heat required.
Hope you got your answer!
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