Question

Melting point of three substances A, B and C are 52°C, 175 °C and 80
°C. Arrange them in the increasing order of the interparticle force of
attraction in each of them.

Answer 1

Answer:

Hi Dear !

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Melting Point Of Substance A = 52°   Celsius  

Melting Point Of Substance B = 175° Celsius

Melting Point Of Substance C = 80°   Celsius

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Descending Order of inter particle force of attraction is :

175° Celsius > 80° Celsius > 52° Celsius  

because , inter molecular force of attraction would increase when melting point rises .

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Explanation:

B will have more inter molecular force of attraction because B's particles are tightly packed and hence does not melt easily.

And A has the least inter molecular force of attraction and hence will melt easily. So descending order would be B, C, A

Answer 2

Answer

A<C <B

Explanation

in the substance with low melting point will have less interstitial space in them. so the attraction force also will be more in the object with high melting point

So your answer is A<C<B

Hope it helps you