Men on each other side of a temple of 40 m height observed it is stop at the angle of elevation 45 degrees in 60° respectively find the distance between the two men.
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Two men on either side of a temple of 30 m height observe its top at the angles of elevation 30
∘
and 60
∘
respectively. Find the distance between the two men.
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Let AB be the height of the temple and P and Q are the two men on either side of the temple.
Given that,
AB=30 m, ∠APB=30
∘
,∠AQB=60
∘
In △ABP,
tan(∠APB)=
PB
AB
tan30
∘
=
PB
30 m
PB=30
3
m
In △ABP,
tan(∠AQB)=
QB
AB
tan60
∘
=
QB
30 m
QB=
3
m
30
QB=10
3
m
Now, PQ=PB+QB=30
3
m+10
3
m
So, PQ=40
3
m
Therefore, distance between two men, i.e. PQ=40
3
m
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