Menna's age is three times the sum of the ages of her two children. After four years her age will be twice the sum of the age of her two children. What us her present age ?
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Let Meena's one child's present age be x years. And second one's be years.
ATQ, Age of Meena = 3 ( x + y ) --> ( i )
After 4 years,
Age of Meena = 2 (x + 4 + y +4 )
3 ( x+ y ) = 2 ( x + y + 8 )
3x + 3y = 2x + 2y + 16
X + y = 16
Putting value of ( x + y ) in ( i ),
3 ( x+ y ) = 3 × 16 = 48 years.
So, Meena's Present age is 48 years.
ATQ, Age of Meena = 3 ( x + y ) --> ( i )
After 4 years,
Age of Meena = 2 (x + 4 + y +4 )
3 ( x+ y ) = 2 ( x + y + 8 )
3x + 3y = 2x + 2y + 16
X + y = 16
Putting value of ( x + y ) in ( i ),
3 ( x+ y ) = 3 × 16 = 48 years.
So, Meena's Present age is 48 years.
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