Question

Menna went to a bank to withdraw RS 2000. She asked the cashier to give her RS 50 and RS 100 notes only. Menna got 25 notes in all. represent this situation algebraically​

Answer 1

Answer:

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Let the Rs.50 notes by x and Rs.100 notes be y.

∴ Total notes =(x+y) notes

Total notes (given) =25 notes

∴(x+y)=25⟶(i)

Total money Meena has=50x+100y

Total money (given) =Rs.2000

On simplification, 

x+2y=40⟶(ii)

On substraction (i) and (ii),

−y=−15

y=15 notes

putting y in (i)

x+y=25

x=10 notes

∴ Rs.50 notes=10 notes.

  

 Rs.100 notes=15 notes. 

Answer 2

Step-by-step explanation:

Let no. of Rs. 50 notes = X

no. of Rs. 100 notes = y

Total notes = 25

⇒ x+y=25

⇒ x = 25-y

total amount only in Rs. 50 notes = 50x

total amount only in Rs. 100 notes = 100y

Total amount = 2000

→ 50x + 100y = 2000 50(25-y) + 100y = 2000

→ 50×25-50y + 100y = 2000

1250 +50 y = 2000 → 50y = 2000-1250 = 750

⇒ y = 750/50 = 15

x = 25-15 10

No. of Rs. 50 notes = 10

No. of Rs. 100 notes = 15