Question

Mention the mass percent of carbon in CH3COOH. (C = 12, H = 1, O = 16 g mol-1)​

Answer 1

Answer:

Explanation:

Molecular mass of ethanoic acid (CH

3

​

COOH)=1×C+3×H+1×C+2×O+1×H=12+3+12+32+1=60u

This will help you

Answer 2

Given - Compound CH3COOH

Find - Mass percent of carbon in CH3COOH

Solution - To find mass percent of carbon, the formula used will be : mass of element in 1 mole of compound/molar mass of compound * 100

Mass of carbon in 1 mole of compound = 12 + 12 = 24 gram

Molar mass of CH3COOH = 12 + (1*3) + 12 + 16 + 16 + 1

= 60

Keeping the values in formula -

Mass percentage = (24/60)*100

Mass percentage = 40%.

Hence, mass percent of Carbon in CH3COOH is 40%.