Mention the shape and type of hybridisation of pcl5 and sf6
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hybridisation = no. of valence e' + monobonding atom / 2 ,pcl5 =5+5/2=5 ,sp3d same process in next
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Answer:
Explanation:
No of bonds formed=1/2(no of valence electrons +ligands+anion-cation) hope this helps you
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