mera exam hai help two tuning fork when sounded simultaneously give on beat each 0.4s what is difference in frequnices
Answers
Answered by
0
the answer is
t=1/[2(n1-n2)]
0.4=1/2(n1-n2)
0.8=1/(n1-n2)
n1-n2=1/0.8
n1-n2=1.25sec.
hope the answer is helpful.
t=1/[2(n1-n2)]
0.4=1/2(n1-n2)
0.8=1/(n1-n2)
n1-n2=1/0.8
n1-n2=1.25sec.
hope the answer is helpful.
Similar questions