Hindi, asked by kukur57889, 4 months ago

mera last pic in Jammu and Kashmir ka kal Rajasthan jana hai

btw kal mera b day bhi hai aur meri ek pyari bahan iss app main hai but wo mere se naraj hai kiunki wo mujhe bohot miss kar rahi hai

main kar raha hun sabko miss

pata ni kab ye jaan nikle jaega ?

bas ek dua hai main bas ek bar apne family se mil jaun aur apne bahan ko dekh lun phir chain ka nind soo jaunga

# Jay Hind # ​

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Answers

Answered by mayankkumarmk1212
3

Answer:

given : ABCD is a square

diagonal AC and BD intersect at O

also with side an isosceles triangle BEC right angled at E is drawn

to prove : OBEC is a square

proof :

AC = BD (Diagonals of square are equal )....eq.1

a square is a type of rhombus with opp. sides equal

diagonals of rhombus bisect each other at right angle

so AO= OC...eq.2

BO= OD...eq 3

and angle 1 = 90 degree

from above 3 equations OB= OC

angle 3 = angle 2 ( angles opp. to equal sides are equal )

in triangle BOC

angle 1 + angle 2 + angle3= 180degree ( angles sum prop. of a triangle)

90 degree + 2(angle 3)=180degree

( angle2 = angle3)

2(angle3) = 180degree-90degree= 90degree

angle3= 90/2 = 45 degree

angle 2 = angle3 = 45 degree

in triangle BEC

BE = CE (Given)

so angle CBE = angle ECB ( angles opp. to equal sides are equal)

and angle E = 90 degree

by applying angle sum property of triangle BEC

WE find that angle CBE = angle ECB = 45degree

in triangle BOC and triangle BEC

angle 1 = angle BEC ( 90 degree each)

angle 3 = angle ECB ( 45 degree each)

BC= BC ( common)

by AAS congruence axiom

triangle BOC = triangle BEC

OB= OE (cpct)

now we find that all sides are equal in quad. OBEC and angles are of 90 degree each

so OBEC is a square

hope it helps u..

Explanation:

JaI hind


kukur57889: jai hind
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