mera last pic in Jammu and Kashmir ka kal Rajasthan jana hai
btw kal mera b day bhi hai aur meri ek pyari bahan iss app main hai but wo mere se naraj hai kiunki wo mujhe bohot miss kar rahi hai
main kar raha hun sabko miss
pata ni kab ye jaan nikle jaega ?
bas ek dua hai main bas ek bar apne family se mil jaun aur apne bahan ko dekh lun phir chain ka nind soo jaunga
# Jay Hind #
Answers
Answer:
given : ABCD is a square
diagonal AC and BD intersect at O
also with side an isosceles triangle BEC right angled at E is drawn
to prove : OBEC is a square
proof :
AC = BD (Diagonals of square are equal )....eq.1
a square is a type of rhombus with opp. sides equal
diagonals of rhombus bisect each other at right angle
so AO= OC...eq.2
BO= OD...eq 3
and angle 1 = 90 degree
from above 3 equations OB= OC
angle 3 = angle 2 ( angles opp. to equal sides are equal )
in triangle BOC
angle 1 + angle 2 + angle3= 180degree ( angles sum prop. of a triangle)
90 degree + 2(angle 3)=180degree
( angle2 = angle3)
2(angle3) = 180degree-90degree= 90degree
angle3= 90/2 = 45 degree
angle 2 = angle3 = 45 degree
in triangle BEC
BE = CE (Given)
so angle CBE = angle ECB ( angles opp. to equal sides are equal)
and angle E = 90 degree
by applying angle sum property of triangle BEC
WE find that angle CBE = angle ECB = 45degree
in triangle BOC and triangle BEC
angle 1 = angle BEC ( 90 degree each)
angle 3 = angle ECB ( 45 degree each)
BC= BC ( common)
by AAS congruence axiom
triangle BOC = triangle BEC
OB= OE (cpct)
now we find that all sides are equal in quad. OBEC and angles are of 90 degree each
so OBEC is a square
hope it helps u..
Explanation:
JaI hind