Question

mera t
solve the attachment↑​

Answer 1

Step-by-step explanation:

hello didi

kese ho. aap

$\fcolorbox{blue}{green}{answer}$

Explanation:

To solve this kind of questions, we need to know the oxidation states of different ions.

So we consider the oxidation state of the ion ' R' to be x

And we should be knowing that the oxidation state of a phospate ion is 3-.

The compound is made up of 2 ions basically:

$R ^ x and PO^ {3-} _{4}$

Now arrange these numbers and variables to form an equation

$\rightarrow x + (- 3) = 0$

$\fcolorbox{red}{green}{x = 3}$

Therefore the oxidation state of ion ' R' is 3+

The formula of hydroxide of R will be:

Cross multiply the valencies.

$\big{R = 3}$

$\red{OH = 1}$

$R(OH)_{3}$

$R = 3$

The formula of the sulfide of R will be as follows:

$R = 3$

$S = 2$

$R_{2} S_{3}$

Answer 2

Answer:

17 is the answer please mark as branliest