merchant has three kinds of milk for 435 or 493 litres and 551 litres and the least number of cacks equal size required to store all the milk without machine
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heya......
As minimum number of containers are required, the size of the container should be maximum and the size is also equal.
so size of the container will be HCF of 493, 551 and 435
i.e., 29 So,
required number of containers is = (493+551+435) / 29 = 51
tysm........#gozmit
As minimum number of containers are required, the size of the container should be maximum and the size is also equal.
so size of the container will be HCF of 493, 551 and 435
i.e., 29 So,
required number of containers is = (493+551+435) / 29 = 51
tysm........#gozmit
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