mercuric chloride reacts with ammonia gas and form white precipitate.The molecular formula of white precipitate is-
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Ans :HgNH2Cl , ammoniated Mercury chloride .
when ammonia gas ( NH3) reacts with mercuric chloride ( Hg2Cl2), gives metallic Mercury in black color and mercuric amidochloride precipitated in white color.
e.g., Hg2Cl2 + NH3 ---->HgNH2Cl↓(white precipitate) + Hg(l) + NH4+ + Cl-.
this reaction is an example of disproportionation reaction . because 'Hg' be oxidise as well as reduce.
Hg2Cl2 ------>Hg , Here Hg is reduced ,while Hg2Cl2------>HgNH2Cl, here Hg is oxidised.
when ammonia gas ( NH3) reacts with mercuric chloride ( Hg2Cl2), gives metallic Mercury in black color and mercuric amidochloride precipitated in white color.
e.g., Hg2Cl2 + NH3 ---->HgNH2Cl↓(white precipitate) + Hg(l) + NH4+ + Cl-.
this reaction is an example of disproportionation reaction . because 'Hg' be oxidise as well as reduce.
Hg2Cl2 ------>Hg , Here Hg is reduced ,while Hg2Cl2------>HgNH2Cl, here Hg is oxidised.
rishilaugh:
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Molecular Formula of White precipitate is Hg(NH2)Cl
Explanation:
Ammonia Solution reacts with mercury(I) chloride and forms white precipitate of Mercury(II) amidochloride and mercury metal . Both the products are insoluble precipitates.
Mercury(II)amido chloride is a white precipitate but the finely divided mercury makes its shiny black.
Hg2Cl2↓ + 2NH3 -------> Hg ↓+ Hg(NH2)Cl ↓ +NH4⁺ + Cl⁻
The above reaction can be used to differentiate the mercury(I) ions from lead (II) and silver (I)
Explanation:
Ammonia Solution reacts with mercury(I) chloride and forms white precipitate of Mercury(II) amidochloride and mercury metal . Both the products are insoluble precipitates.
Mercury(II)amido chloride is a white precipitate but the finely divided mercury makes its shiny black.
Hg2Cl2↓ + 2NH3 -------> Hg ↓+ Hg(NH2)Cl ↓ +NH4⁺ + Cl⁻
The above reaction can be used to differentiate the mercury(I) ions from lead (II) and silver (I)
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