Question

mere pyare brainly vasiyo yh question kro do yrr❤️❤️​

Answer 1

Answer:

see attachment..

HOPE IT HELPS......

Answer 2

AnswEr :

$\:\bullet\:\sf\ Let \: \alpha, \beta and \gamma \: be \: the \: zeroes \: of \: polynomial$

$\rule{100}1$

$\underline{\bigstar\:\textsf{According \: to \: the \: question\: now;}}$

$\normalsize\mathbb{\underline{SUM \: OF \: ZEROES : }}$

$\normalsize\dashrightarrow\sf\ \alpha + \beta + \gamma = \frac{-b}{a}$

$\normalsize\dashrightarrow\sf\frac{2}{1} = \frac{-b}{a}$

$\normalsize\mathbb{\underline{PRODUFT \: OF \: ZEROES \: TAKEN \: TWO \: AT \: A \: TIME : }}$

$\normalsize\dashrightarrow\sf\ \alpha\beta + \beta\gamma + \alpha\gamma = \frac{c}{a}$

$\normalsize\dashrightarrow\sf\frac{-7}{1} = \frac{c}{a}$

$\normalsize\mathbb{\underline{ PRODUCT \: OF \: ZEROES : }}$

$\normalsize\dashrightarrow\sf\ \alpha\beta\gamma = \frac{-d}{a}$

$\normalsize\dashrightarrow\sf\frac{-14}{1} = \frac{-d}{a}$

$\rule{100}1$

$\normalsize\sf\ From \: this \: we \: get :$

$\:\bullet\:\sf\ a = 1$

$\:\bullet\:\sf\ b = -2$

$\:\bullet\:\sf\ c = -7$

$\:\bullet\:\sf\ d = 14$

$\rule{100}1$

$\normalsize\sf\ Now, \: the \: polynomial \: is :$

$\normalsize\star{\boxed{\sf{ P(x) = ax^3 + bx^2 + cx + d }}}$

$\scriptsize\sf{ \: \: \: \: \: \: \: \: \: \dag\ Block \: the \: values\: in \: available \: data}$

$\normalsize\dashrightarrow\sf\ P(x) = 1(x^3) + (-2)(x^2) + (-7)(x) + 14$

$\normalsize\dashrightarrow\sf\ P(x) = x^3 - 2x^2 - 7x + 14$

$\normalsize\dashrightarrow{\boxed{\sf \blue{ P(x) = x^3 - 2x^2 - 7x + 14}}}$