Question

Meri madat karo plzzz​

Answer 1

Answer:

p31 = m1×v1 = 0.2×5 = 1 Ns

p2 = m1×v2 = 0.2 × 17 = 3.4 .

formula used p = mv

hence Δp = p2 - p1 = 3.4-1 = 2.4 Ns answer...

Answer 2

3) Mass = 200 g = 0.2 kg ; Initial velocity = 5 m/s ; Final velocity = 17 m/s.

Change in linear momentum = m(v-u) unit = 0.2(17-5) Ns = 0.2×12 Ns = 2.4 Ns

4) As we know that MASS IS A CONSTANT QUANTITY, so, the value of the mass of the motorcycle will remain fixed, i.e., unchanged.

As we know that MASS IS A CONSTANT QUANTITY, so, the value of the mass of the motorcycle will remain fixed, i.e., unchanged.Initially, the linear momentum of the motorcycle = (100×10) Ns = 1000 Ns

As we know that MASS IS A CONSTANT QUANTITY, so, the value of the mass of the motorcycle will remain fixed, i.e., unchanged.Initially, the linear momentum of the motorcycle = (100×10) Ns = 1000 NsNew linear momentum = (1000+2000) Ns = 3000 Ns

As we know that MASS IS A CONSTANT QUANTITY, so, the value of the mass of the motorcycle will remain fixed, i.e., unchanged.Initially, the linear momentum of the motorcycle = (100×10) Ns = 1000 NsNew linear momentum = (1000+2000) Ns = 3000 NsSo, New velocity = New momentum/Mass = (3000/100) m/s = 30 m/s