Question

metal A belongs to period 3 and group 13,A in red hot condition reacts with steam to form B. A with strong alkali [NaOH] forms C. find A,B,C with reactions ​

Answer 1

Answer:

Metal A be aluminum

Reaction with steam:

2 Al + 3H2O gives Al2 O3 +3H2 liberation

Reaction with strong alkali [NaOH] :

2Al + 2NAOH +2 H2O gives 2Na Al O2 +3H2 liberation

Results :

A - aluminum

B - alumina

C - sodium meta aluminate

Answer 2

Answer:

that's correct the answer is correct