Metal A has electronic configuration2,8,1and metal B has 2,8,8,2 which is more reactive , identify these metals and give the reaction with did HCL
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metal A is more reactive which is sodium
and metal B is magnesium which is less reactive than sodium
and metal B is magnesium which is less reactive than sodium
veer20:
because Na is alkali metal when any alkali react with water it catches fire easily
so they hv highly reactivity when we go down in first theri reactivity increased
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Atomic no of Metal A is 2 + 8 + 1 = 11
So, Metal A is Sodium.
Atomic no of Metal B is 2 + 8 + 8 + 2 = 20
So, Metal B is Calcium.
Sodium is more reactive than calcium according to the Reactivity series.
Reaction of Sodium with HCl :
2Na + 2HCl -> 2NaCl + H2
Reaction of Calcium with HCl :
Ca + 2HCl -> CaCl2 + H2
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So, Metal A is Sodium.
Atomic no of Metal B is 2 + 8 + 8 + 2 = 20
So, Metal B is Calcium.
Sodium is more reactive than calcium according to the Reactivity series.
Reaction of Sodium with HCl :
2Na + 2HCl -> 2NaCl + H2
Reaction of Calcium with HCl :
Ca + 2HCl -> CaCl2 + H2
Hope this helps you... Please mark it as brainliest!!!
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