Question

Metal ′ A ′ is 20 times heavier than iron and metal ′ B ′ is 13 times heavier than iron. In what proportion must these two metals be mixed to obtain an alloy which is 17 times heavier than iron.

Answer 1

Given : Metal  A  is 20  times heavier than iron and metal  B   is  13  times heavier than iron.

To Find : In what proportion must these two metals be mixed to obtain an alloy which is  17  times heavier than iron

Solution:

20 times heavier  =  A

then weight = 20A

13 times heavier = B

then weight  = 13B

Total weight = 20A + 13B     = 17 ( A  + B )

=> 20A + 13B = 17A + 17B

=> 3A  = 4B

=> A/B  =  4 /3

=> A : B = 4 : 3

4 : 3 proportion in which metal A & Metal B must these two metals be mixed to obtain an alloy which is  17  times heavier than iron

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