Metal ′A′ is 20 times heavier than iron and metal ′B′ is 13 times heavier than iron. In what proportion must these two metals be mixed to obtain an alloy which is 17 times heavier than iron.
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metal A and metal B is mixed in proportion 4: 3
One method is in the attachment
(or)
In average formula
x and y be ratio of metal A and Metal B
(20 x + 13 y ) / (x+y) = 17
3x = 4y
x/y = 4/3
metal a : metal b = 4:3
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