Question

Metal block weighs 500 gf in air and 460 gf when completely immersed in water.calculate the upthrust on the block

Answer 1

Answer:

Weight of the body in air =500gf

Weight of the body in water =450gf

∴ (i) loss of weight of the body when immersed in water =500gf−450gf=50gf.

(ii) upthrust of the body=loss in weight of the body =50gf.

(iii) upthrust =Vdg

⇒50gf×g=V×1gcm

−3

×g(densityofwater=1gcm

−3

)

⇒volumeofthebodyV=50cm

3

.

Explanation:

Answer 2

Hola (◔‿◔)

$\Large{\underline{\underline{\red{\bold{☆Question:}}}}}$

Metal block weighs 500 gf in air and 460 gf when completely immersed in water.Then, Calculate the upthrust on the block.

$\Large{\underline{\underline{\bold{☆Given:}}}}$

• Weight of Metal block in air = 500 gf
• Weight of Metal block in Water = 460 gf

$\Large{\underline{\underline{\blue{\bold{➸ ՏϴᏞႮͲᏆϴΝ:}}}}}$

Relation of loss of weight in the body

$\pink{\sf{๛\; Ｆ = Ｗ - ｗ}}$

Where, W is weight of Block in air & w is weight of Block in water

$f = 500gf - 460gf \\ f = 40gf$

The loss of weight in the weight of the block is 40gf, Since the loss of weight is equals to the upthrust on the block.

Upthrust on the block ☞ $\Large\boxed{\blue{40gf}}$

$\boxed{\tt{@MrSovereign}}$

Hope This Helps!!