Metal chloride has x grams of m or y grams chloride awt of metal if it's valency is 3
Answers
Explanation:
Explanation:
For this compound, the equivalent mass of the metal represents the mass of metal that combines with exactly "35.5 g" of chlorine.
You know that the total mass of the oxide is equal to x "g" and that this sample contains y "g" of metal, so you can say that the mass of chlorine present in the sample is equal to
overbrace(xcolor(white)(.)"g")^(color(blue)("mass of metal chloride")) - overbrace(ycolor(white)(.)"g")^(color(blue)("mass of metal")) = overbrace((x-y)color(white)(.)"g")^(color(blue)("mass of chlorine"))
So, you know that y "g" of metal combine with (x-y) "g" of chlorine, so you can say that "35.5 g" of chlorine will combine with
35.5 color(red)(cancel(color(black)("g Cl"))) * (y color(white)(.)"g metal")/((x-y)color(red)(cancel(color(black)("g Cl")))) = (35.5 * y/(x-y))color(white)(.)"g metal"
Therefore, the equivalent mass of the metal in this compound is equal to
color(darkgreen)(ul(color(black)("equivalent mass" = (35.5 * y/(x-y))color(white)(.)"g")))
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