Question

Metal M forms two oxides A & B in which of the ratio of oxygen atoms to the total number of atoms Present in the molecule is 3:5 and 1:3. Determine the formula of A and B


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Answer 1

$\huge\sf\pink{Answer}$

☞ $\sf A = M_2O_3$

☞ $\sf B = MO$

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$\huge\sf\blue{Given}$

✭ Metal M forms two oxides A & B

✭ Oxygen atoms to the total number of atoms present in the molecule is 3:5 and 1:2

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$\huge\sf\gray{To \:Find}$

◈ The formula of A & B?

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$\huge\sf\purple{Steps}$

$\large \underline{\underline{\sf Let}}$

◕ $\sf A be M^{+a}$

◕ $\sf B be M^{+n}$

☯ $\underline{\textsf{As Per the Question}}$

➝ $\sf Formula of A is M^{+a}O^{-2}$

➝ $\sf M_2O_a$

➝ $\sf \dfrac{a}{2+a} = \dfrac{3}{5}$

➝ $\sf 5(a) = 3(2+a)$

➝ $\sf 5a = 6+3a$

➝ $\sf 5a-3a = 6$

➝ $\sf 2a = 6$

➝ $\sf a = \dfrac{6}{2}$

➝ $\sf a = 3$

$\sf \red{\therefore A \dashrightarrow M_2O_3}$

So now then the formula of B will be $\sf M^{+b} O^{-2}$

➳ $\sf M_2O_b$

➳ $\sf \dfrac{b}{2+b} = \dfrac{1}{2}$

➳ $\sf 2(b) = 1(2+b)$

➳ $\sf 2b = 2+b$

➳ $\sf 2b-b = 2$

➳ $\sf b = 2$

$\sf \orange{\therefore B \dashrightarrow MO}$

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