Question

Metal X forms two oxides. Formula of first oxide is
ХО,
2. The first oxide contains 50% of oxygen. If the
second oxide contains 60% of oxygen, the formula of
second oxide is​

Answer 1

The first oxide XO2 contains 50% oxygen.

32/32 + X = 0.5

Molecular weight of the metal x = 32

Now, let the molecular formula of the other metal oxide be MOn:

16n/16n + 32 = 0.6

So, n = 3.

Thus, the formula of 2nd oxide is XO3.

Hope it helps you buddy.

​

.