Question

metallic sphere 1 dm in diameter is beaten into a circular sheet of uniform thickness equal to 1 millimetre .find the radius of sheet.

Answer 1

Area of circle × thickness = Volume of sphere


πr^2×1/100 dm =4/3π(1/2dm)^3. r^2=4/3×1/8×100dm^2. r^2=100/6 dm^2. r=√100/6dm^2. =10/√6 dm

Answer 2

$<i><b>$Answer:

Radius of circular sheet is 40.8 cm.

Step-by-step explanation:

SOLUTION :  

Given :  

Diameter of a metallic sphere = 1 dm = 1 × 10 = 10 cm

[1 dm = 10 cm]

Thickness of circular sheet ,h = 1 mm = 1/10 cm  

[1 mm = 1/10 cm]

Radius of metallic sphere, R = 10/2 = 5 cm

Volume of metallic sphere,V1 = 4/3 πR³

V1 = 4/3 × π × 5³ = 4/3 × π × 125 = 500π/3 cm³

Let ,r be the radius of the circular sheet

Volume of circular sheet = Volume of metallic sphere

πr²h = 500π/3

r²(1/10) = 500/3

r² =  (500 × 10)/3  

r² = 5000/3  

r = √5000/3 = √1666.67

r = 40.8 cm

Hence, the Radius of circular sheet is 40.8 cm.

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