Metallic spheres of radii 6cm,8cm and 10cm are melted and recasted into a single solid sphere.find the surface area of the solid apherw formed
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Let the radius of sphere formed be R
r1 = 6cm
r2 = 8cm
r3 = 10cm
sum of volume of three metallic sphere = volume of the sphere recasted
4/3πr1^3 + 4/3πr2^3 + 4/3πr3^3 = 4/3πR^3
4/3 π ( r1^3 + r2^3 + r3^3) = 4/3 π R^3
r1^3 + r2^3 + r3^3 = R^3
6^3 + 8^3 + 10^3 = R^3
216 + 512 + 1000 = R^3
1728 = R^3
12 cm = R = radius of recasted sphere
Surface area of recasted sphere = 4πR^2
= 4 × 22/7 × 12 × 12
Ans. Surface area of recasted sphere = 1810.28 cm^2
r1 = 6cm
r2 = 8cm
r3 = 10cm
sum of volume of three metallic sphere = volume of the sphere recasted
4/3πr1^3 + 4/3πr2^3 + 4/3πr3^3 = 4/3πR^3
4/3 π ( r1^3 + r2^3 + r3^3) = 4/3 π R^3
r1^3 + r2^3 + r3^3 = R^3
6^3 + 8^3 + 10^3 = R^3
216 + 512 + 1000 = R^3
1728 = R^3
12 cm = R = radius of recasted sphere
Surface area of recasted sphere = 4πR^2
= 4 × 22/7 × 12 × 12
Ans. Surface area of recasted sphere = 1810.28 cm^2
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