Question

Metallic tin in the presence of HCl is oxidised by K2Cr2O7 to stannic chloride SnCl4 . What volume of decinormal dichromate solution would be reduced by 1g of tin.

Answer 1

Here is your answer
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Sn                           →           Sn4+        +             4e 

6e           +             Cr26+       →           2Cr3+




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Therefore,          Meq. of Sn = Meq. of K2Cr2O7

                .       1/(118.7/4) × 1000 = 1/10 × V         

                              

=>                    V = 336.98 mL  


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Answer 2

hy
here is your answer
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We have, the redox changes as,

➡Sn                           →           Sn4+        +             4e 

➡6e           +             Cr26+       →           2Cr3+

➡Therefore,          Meq. of Sn = Meq. of K2Cr2O7

➡Or,                          1/ESn × 1000 = 1/10 × V

➡Or,                          1/(118.7/4) × 1000 = 1/10 × V         

      ➡                         [As, Eq. wt. of Sn = (At.wt.)/4]

➡Or,                        V = 336.98 mLans
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