Question

meter rule is balanced by placing the knife edge at 50 cm mark and suspending a weight of 20 gf from 0 end.The centre of gravity of the ruler is

2 points

at the centre ie 50 cm mark

towards the right of 50 cm mark

towards the left of the 50 cm mark ie towards 20 gf weight

none of these

​

Answer 1

Answer:

Explanation:

The center of gravity of a uniform half meter rule is 25 cm.

The rule balances horizontally on a knife edge at 29 cm mark when a weight of 20 kgf is suspended from one end.

The difference in the center of gravity and the point of balance=29−25=4cm(Y)

The weight is suspended at one of the extremes,

Let us assume at the 50 cm end.

Therefore, the distance from the point of knife edge to the weight =50−29=21cm(X)

Weight of meter rule =YX​× Suspended weight

∴ Weight of meter rule =421​×20=105 kgf

Answer 2

Answer:

option c- towards the left of the 50 cm mark ie towards 20 gf weight.