Question

Methane and propane both are constituents of natural gas .A sample of methane contains 5.7g of C and 1.9g of H atom combined in certain way .Whereas A sample of propane contain 4.47g of C and 0.993g of H combined in different way .Show that two sample obey law of multiple proportion

Answer 1

Answer:

They obey law of multiple proportion.

Explanation:

Methane CH4

C=5.7/12=0.5 mol

H= 1.9/1.008=2 mol

Ratio : 1:4

Propane C3H8

C= 4.47/12= 0.4

H= 0.99/1.008= 1

Ratio : 1:8

Answer 2

Answer:

good your are

Explanation:

very nice