Question

Methane gas burns in air according to the following reaction.
CH4 + 202 → CO2 + 2H20
If 8 g of methane is burnt, what volume of CO2 measured at S.T.P. will be produced ?​

Answer 1

Answer:

answer is 11.2 L

Explanation:

molar mass of CH4 is 16 g

16g methane produces 22.4 L

1g methane produces 1.4 L

then, 8g methane produces 11.2 L.

OR,

16 g methane produces 22. L at STP

1 mole produces 22.4 L

then half mole produces 11.2 L at STP.

Thank you