Question

Method for calculation of empirical and molecular formula

Answer 1

☆☆AS-SALAMU-ALYKUM ☆☆

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CALCULATION OF EMPIRICAL FORMULA :-
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PERCENTAGE OF CARBON = MASS OF CARBON DIOXIDE CONTRIBUTED ÷MASS OF ORGANIC COMPOUND ×12÷44×100

PERCENTAGE OF HYDROGEN = MASS OF HYDROGEN ÷ ATOMIC MASS OF ORGANIC COMPOUND × 2.02÷18.02×100

MOLES OF CARBON = %OF CARBON ÷ATOMIC MASS OF CARBON

MOLES OF HYDROGEN =%OF HYDROGEN ÷ATOMIC MASS OF ORGANIC COMPOUND

MOLES OF OXYGEN =%OF OXYGEN ÷ ATOMIC MASS OF ORGANIC COMPOUND

SECOND STEP :-
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FIND OUT SIMPLEST RATIO

METHOD OF FINDING SIMPLEST RATIO :-

DIVIDE NUMVBER OF MOLES OF EACH ELEMENT BY THE SMALLEST NUMBER OF MOLES .

NOW :-
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IF RATIO IS NOT IN WHOLE NUMBER THEN :-

MULTIPLY NUMBER OF MOLES OF EACH ELEMENT BY A SUITABLE NUMBER SO AS TO GET WHOLE NUMBER .

FINAL STEP :-
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WRITE SYMBOL OF EACH ELEMENT WITH NUMBER OF MOLES AS SUBSCRIPT

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CALCULATION OF MOLECULAR FORMULA :-
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MOLECULAR FORMULA =n × EMPIRICAL FORMULA

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THERE ARE THREE ATTACHMENTS , THESE ARE EXAMPLE OF EMPIRICAL FORMULA AND MOLECULAR FORMULA

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♡♤♡INSHALLAH IT WILL HELP U ♡♤♡

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HAVE A NICE EVENING ☺☺☺☺☺