Question

method:
(i) x + y = 5 and 2x – 3y = 4​

Answer 1

Answer:

By elimination method

x + y =5 ……….(1)

2x –3y = 4 ………(2)

Multiplying equation (1) by 2, we obtain

2x + 2y = 10 ………..(3)

2x –3y = 4 ………(2)

Subtracting equation (2) from equation (3), we obtain

5y = 6

y = 6/5

Substituting the value in equation (1), we obtain

x = 5 - (6/5) = 19/5

So our answer is x = 19/5 and y = 6/5

By substitution method

x + y =5 ……….(1)

subtract y both side we get

x = 5 - y ……..,(4)

plug the value of x in equation second we get

2(5 – y ) – 3y = 4

-5y = - 6

y = -6/-5 = 6/5

Plug the value of y in equation 4 we get

x = 5 – 6/5

x = 19/5

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

x + y = 5.....(1)

2x -3y = 4......(2)

multiply equ.(1) by 2.

2x + 2y = 10....(3)

Subtracting equ.(2) from (3)

5y = 6

y= 6/5

x + y = 5

x + 6/5 = 5

x = 5 - 6/5

x= 19/5

x= 19/5

y=6/5

Hope it helps you.