method is essential... Please help
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Step-by-step explanation:
4a²+1/a²=2
(2a)²+(1/a)²=2
(2a+1/a)²-2(2a)(1/a)=2
(2a+1/a)²-4=2
(2a+1/a)=√6......(eq1)
cubing both sides
(2a+1/a)³=(√6)³
(2a)³+(1/a)³+3(2a)(1/a)(2a+1/a)=6√6
8a³+1/a³+6(√6)=6√6 ((2a+1/a)=√6 in eq1)
8a³+1/a³=6√6-6√6=0 answer
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