Question

method of completing square

Answer 1

$5 {x}^{2} - 14x - 3 = 0 \\ 5 {x}^{2} - 14x = 3 \\ {x}^{2} - \frac{14}{5} x = \frac{3}{5} \\ {x}^{2} - 2 \times \frac{7}{5} x + \frac{49}{25} = \frac{3}{5} + \frac{49}{25} \\ {(x - \frac{7}{5}) }^{2} = \frac{15 + 49}{25} \\ x - \frac{7}{5} = + - \sqrt{ \frac{64}{25} } \\ x = \frac{7}{5 } + - \frac{8}{5} \\ x = 3 \: and \: - \frac{1}{5}$
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